Added a script to check 2 clients with same ID fails

tools_scripts/twoClientsWithSameID.groovy

@@ -0,0 +1,34 @@
+@GrabResolver(name='Paho', root='https://repo.eclipse.org/content/repositories/paho-releases/')
+@Grab(group='org.eclipse.paho', module='org.eclipse.paho.client.mqttv3', version='1.0.1', ext='jar')
+
+
+import org.eclipse.paho.client.mqttv3.MqttClient
+import org.eclipse.paho.client.mqttv3.MqttMessage
+import org.eclipse.paho.client.mqttv3.MqttException
+import org.eclipse.paho.client.mqttv3.persist.MqttDefaultFilePersistence
+
+String host = args[0]
+
+String tmpDir = System.getProperty("java.io.tmpdir")
+MqttDefaultFilePersistence dataStore1 = new MqttDefaultFilePersistence(tmpDir + "/client1")
+MqttClient client1 = new MqttClient("tcp://${host}:1883", "ConnectedClient", dataStore1)
+client1.connect()
+println "Client1 connected"
+client1.subscribe("topic", 0)
+println "Client1 subscribed to topic"
+
+sleep(500)
+
+//now connect a second client but with the same ID
+MqttDefaultFilePersistence dataStore2 = new MqttDefaultFilePersistence(tmpDir + "/client2")
+MqttClient client2 = new MqttClient("tcp://${host}:1883", "ConnectedClient", dataStore2)
+client2.connect()
+println "Client2 connected"
+client2.subscribe("topic", 0)
+println "Client2 subscribed to topic"
+
+client1.disconnect()
+println "Client1 disconnected"
+
+client2.disconnect()
+println "Client2 disconnected"